1+a^2-(2a^2+12)1+(7a/10)=7

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Solution for 1+a^2-(2a^2+12)1+(7a/10)=7 equation: 



1+a^2-(2a^2+12)1+(7a/10)=7

We move all terms to the left:

1+a^2-(2a^2+12)1+(7a/10)-(7)=0

We add all the numbers together, and all the variables

a^2-(2a^2+12)1+(+7a/10)+1-7=0

We add all the numbers together, and all the variables

a^2-(2a^2+12)1+(+7a/10)-6=0

We get rid of parentheses

a^2-(2a^2+12)1+7a/10-6=0

We multiply all the terms by the denominator


a^2*10-((2a^2+12)1)*10+7a-6*10=0

We add all the numbers together, and all the variables

a^2*10+7a-((2a^2+12)1)*10-60=0

Wy multiply elements

10a^2+7a-((2a^2+12)1)*10-60=0

We move all terms containing a to the left, all other terms to the right

10a^2+7a-((2a^2+12)1)*10=60

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